Mineola

2010 Census

The village has 18,799 residents as of the 2010 census, with 7,473 households and 4,954 families. 10,337.3 persons per square mile (3,991.3 people/km2) was the population density. At an average density of 4,111.5 per square mile (1,587.5/km2), there were 7,650 dwelling units. There were 81.7% White people living in the village, 71.5% Non-Hispanic White people, 2.0% African Americans, 0.2% Native Americans, 8.5% Asian people, 0.0% Pacific Islanders, 5.3% people of other races, and 2.3% people of two or more races. Any race that is Hispanic or Latino makes up 16.4% of the population.

There were 7,473 households, of which 27.0% included children under the age of 18, 53.2% consisted of married couples, 9.3% included a female householder living alone, and 33.7% did not belong to a family. Individuals made up 29.1% of all households, and 11.8% of those contained a single person 65 years of age or older. 3.20 was the average family size while 2.57 was the average size of a household.

2000 Census

The village has 19,234 residents, 7,473 homes, and 4,954 families as of the 2000 census[34]. 10,337.3 persons per square mile (3,991.3 people/km2) was the population density. At an average density of 4,111.5 per square mile (1,587.5/km2), there were 7,650 dwelling units. With 82.39% of its population being White, 1.03% African American, 0.29% Native American, 4.52% Asian, 0.04% Pacific Islander, 3.93% from other races, and 3.79% from two or more races, the community was ethnically composed. Any race that is Hispanic or Latino makes up 13.03% of the population.

There were 7,473 households, of which 27.0% included children under the age of 18, 53.2% consisted of married couples, 9.3% included a female householder living alone, and 33.7% did not belong to a family.